a) Sửa đề
x4+2x3+x2
=(x4+x3)+(x3+x2)
=x3(x+1)+x2(x+1)
=(x+1)(x3+x2)
=(x+1).x2(x+1)
=x2(x+1)2
b) x3−x+3x2y+3xy2+y3−y
=(x3+3x2y+3xy2+y3)−(x+y)
=(x+y)3−(x+y)
=(x+y)[(x+y)2−1]
=(x+y)(x+y−1)(x+y+1)
c) 5x2−10xy+5y2−20z2
=5(x2−2xy+y2−4z2)
=5[(x−y)2−(2z)2]
=5(x−y−2z)(x−y+2z)