Giải thích các bước giải:
$x-\dfrac{3(x+30)}{15}-29\dfrac 12=\dfrac{7x}{10}-\dfrac{2(10x+2)}{5}$
$\to x-\dfrac{3(x+30)}{15}-\dfrac{59}{2}=\dfrac{7x}{10}-\dfrac{2(10x+2)}{5}$
$\to x-\dfrac{x+30}{5}-\dfrac{59}{2}=\dfrac{7x}{10}-\dfrac{2\left(10x+2\right)}{5}$
$\to 10x-2\left(x+30\right)-295=7x-4\left(10x+2\right)$
$\to 8x-355=7x-40x-8$
$\to 41x=347$
$\to x=\dfrac{347}{41}$