$|15 - 3x| = x + 7 $ $(1)$
ĐK: $x+7$ $\geq0$ ⇒ $x\geq-7$
$(1)$ ⇒ \(\left[ \begin{array}{l}15-3x=x+7\\15-3x=-x-7\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}-3x-x=-15+7\\x-3x=-15-7\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}-4x=-8\\-2x=-22\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=2\\x=11\end{array}(TMĐK) \right.\)
Vậy $x=2$ hoặc $x=11$
