A.\(2\ln \left( {x + 1} \right) + \dfrac{1}{{x + 1}} + C\)
B.\(\ln \left( {x + 1} \right) - \dfrac{2}{{x + 1}} + C\)
C.\(2\ln \left( {x + 1} \right) + \dfrac{2}{{x + 1}} + C\) 
D.\(2\ln \left( {x + 1} \right) - \dfrac{1}{{x + 1}} + C\)

A.\(64\)
B.\(81\)
C.\(\dfrac{3}{4}\)
D.\(12\)

A.\(\dfrac{x}{1} + \dfrac{y}{{ - 2}} + \dfrac{z}{{ - 3}} = 0\)
B.\(\dfrac{x}{{ - 1}} + \dfrac{y}{{ - 2}} + \dfrac{z}{3} = 1\)
C.\(\dfrac{x}{1} + \dfrac{y}{{ - 2}} + \dfrac{z}{{ - 3}} = 1\)
D.\(\dfrac{x}{{ - 1}} + \dfrac{y}{2} + \dfrac{z}{3} = 1\)

A.\({90^0}\)
B.\({45^0}\)
C.\({60^0}\)
D.\({30^0}\)

A.\(3\)
B.\(1\)
C.\(4\)
D.\(2\)

A.\(\left( { - 1;2} \right)\)
B.\(\left( { - 2;0} \right)\)
C.\(\left( { - 1;0} \right)\)
D.\(\left( {0; + \infty } \right)\)

A.\(40\)
B.\(20\sqrt 2 \)
C.\(4\sqrt {10} \)
D.\(8\)

A.\(\left\{ \begin{array}{l}x = 2 - t\\y = 4 - 4t\\z = 4 - 2t\end{array} \right.\)
B.\(\left\{ \begin{array}{l}x = 1 + t\\y = 2 + 4t\\z = 2 + 2t\end{array} \right.\)
C.\(\left\{ \begin{array}{l}x = 1 + t\\y =  - 4t\\z = 2 + 2t\end{array} \right.\)
D.\(\left\{ \begin{array}{l}x = 1 - t\\y = 4t\\z = 2 + 2t\end{array} \right.\)

A.\(\overrightarrow {{u_3}}  = \left( {3; - 1;2} \right)\)
B.\(\overrightarrow {{u_2}}  = \left( {4;2;3} \right)\)
C.\(\overrightarrow {{u_4}}  = \left( {4; - 1;3} \right)\)
D.\(\overrightarrow {{u_1}}  = \left( {3;1;2} \right)\)

A.\(18\)
B.\(6\)
C.\(8\)
D.\(12\)