A.\(f\left( 2 \right) - 5\)B.\(f\left( { - 1} \right) + 1\)C.\(f\left( 1 \right) - 3\)D.\(f\left( 0 \right)\)
A.\(\dfrac{3}{5}\)B.\(\dfrac{{\sqrt {15} }}{5}\)C.\(\dfrac{{\sqrt {10} }}{5}\)D.\(\dfrac{4}{5}\)
A.\(1\)B.\(3\)C.\(0\)D.\(2\)
A.\(2\)B.\(1\)C.\(4\)D.\(3\)
A.\(\dfrac{5}{{27}}\)B.\(\dfrac{5}{{37}}\)C.\(\dfrac{5}{{32}}\)D.\(\dfrac{1}{3}\)
A.\(\dfrac{{x - 2}}{1} = \dfrac{{y + 3}}{{ - 1}} = \dfrac{{z - 5}}{4}\)B.\(\dfrac{{x - 1}}{1} = \dfrac{{y + 2}}{3} = \dfrac{{z - 1}}{{ - 4}}\)C.\(\dfrac{x}{{ - 1}} = \dfrac{{y - 1}}{3} = \dfrac{{z - 3}}{2}\)D.\(\dfrac{{x - 1}}{{ - 1}} = \dfrac{{y + 2}}{3} = \dfrac{{z - 1}}{2}\)
A.\(5\)B.\(4\)C.\(2\)D.\(7\)
A.\(M = \dfrac{1}{6}N\)B.\(M = \dfrac{3}{2}N\)C.\(M = \dfrac{2}{3}N\)D.\(M = \sqrt N \)
A.\(y = \dfrac{1}{{{x^2} + 1}}\)B.\(y = {x^3} - x\)C.\(y = {3^x}\)D.\(y = \ln x\)
A.\(\overrightarrow {{u_2}} \left( {1; - 2;2} \right)\)B.\(\overrightarrow {{u_1}} \left( {1; - 2; - 1} \right)\)C.\(\overrightarrow {{u_3}} = \left( {2;1;2} \right)\)D.\(\overrightarrow {{u_4}} = \left( {4; - 2;1} \right)\)
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