1)
\({n_{NaOH}} = 0,15.0,5 = 0,075{\text{ mol}}\)
2)
\({m_{N{a_2}C{O_3}}} = 120.5,3\% = 6,36{\text{ gam}}\)
\( \to {n_{N{a_2}C{O_3}}} = \frac{{6,36}}{{23.2 + 60}} = 0,06{\text{ mol}}\)
3)
a)
\(C{\% _{CuS{O_4}}} = \frac{{20}}{{200}} = 10\% \)
b)
\(C{\% _{NaCl}} = \frac{{12}}{{180}} = 6,67\% \)
c)
\({n_{KN{O_3}}} = \frac{{10,1}}{{39 + 14 + 16.3}} = 0,1{\text{ mol}}\)
\( \to {C_{M{\text{ KN}}{{\text{O}}_3}}} = \frac{{0,1}}{{0,3}} = 0,333M\)
d)
\({n_{KCl}} = \frac{{14,9}}{{39 + 35,5}} = 0,2{\text{ mol}}\)
\( \to {C_{M{\text{ KCl}}}} = \frac{{0,2}}{{0,5}} = 0,4M\)