Đáp án:
|X-($\frac{1}{4}$:$\frac{1}{2}$.$\frac{1}{3}$)|= (5-$\frac{1}{3}$):$\frac{2}{3}$
|X-$\frac{1}{6}$|=$\frac{14}{3}$:$\frac{2}{3}$
|X-$\frac{1}{6}$|=7
X-$\frac{1}{6}$=-7 hoặc X-$\frac{1}{6}$=7
X = (-7)+$\frac{1}{6}$ X = 7+$\frac{1}{6}$
X =$\frac{-41}{6}$ X =$\frac{41}{6}$
=> X ∈ {$\frac{-41}{6}$;$\frac{41}{6}$}
Cho mình xin ctlhn nha