$a, x(2x-9)=3x(x-5)$
$⇔2x²-9x=3x²-15x$
$⇔2x²-3x²-9x+15x=0$
$⇔-x²+6x=0$
$⇔-x(x-6)=0$
⇔\(\left[ \begin{array}{l}-x=0\\x-6=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=0\\x=6\end{array} \right.\)
$b, x³-3x²+3x-1=0$
$⇔(x-1)³=0$
$⇔x-1=0$
$⇔x=1$
#CHÚC BẠN HỌC TỐT
#15/1/2021