Em tham khảo nha:
\(\begin{array}{l}
1)\\
{V_O} = 4 \times 2 + 5 - 6 \times 2 = 1l\\
C = \dfrac{{{V_{C{O_2}}}}}{{{V_X}}} = \dfrac{4}{1} = 4\\
H = \dfrac{{2{V_{{H_2}O}}}}{{{V_X}}} = \dfrac{{2 \times 5}}{1} = 10\\
O = \dfrac{{{V_O}}}{{{V_X}}} = \dfrac{1}{1} = 1\\
\Rightarrow CTHH:{C_4}{H_{10}}O\\
2)\\
{n_{C{O_2}}} = \dfrac{{4,4}}{{44}} = 0,1\,mol\\
{n_{{H_2}O}} = \dfrac{{1,8}}{{18}} = 0,1\,mol\\
{n_C} = {n_{C{O_2}}} = 0,1\,mol\\
{n_H} = 2{n_{{H_2}O}} = 0,2\,mol\\
{m_O} = 3 - 0,1 \times 12 - 0,2 = 1,6g\\
{n_O} = \dfrac{{1,6}}{{16}} = 0,1\,mol\\
{n_C}:{n_H}:{n_O} = 0,1:0,2:0,1 = 1:2:1\\
\to CTDGN:C{H_2}O\\
{M_X} = 30 \times 2 = 60g/mol\\
\Rightarrow 30n = 60 \Rightarrow n = 2\\
CTHH:{C_2}{H_4}{O_2}
\end{array}\)