Đáp án:
\(\begin{array}{l} b,\ C_{M_{Ca(OH)_2}}=0,5\ M.\\ c,\ V_{\text{dd H$_2$SO$_4$}}=107,456\ ml.\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l} a,\\ PTHH:\\ CaO+H_2O\to Ca(OH)_2\ (1)\\ Ca(OH)_2+H_2SO_4\to CaSO_4\downarrow+2H_2O\ (2)\\ b,\\ n_{CaO}=\dfrac{14}{56}=0,25\ mol.\\ Theo\ pt\ (1):\ n_{Ca(OH)_2}=n_{CaO}=0,25\ mol.\\ \Rightarrow C_{M_{Ca(OH)_2}}=\dfrac{0,25}{0,5}=0,5\ M.\\ c,\\ Theo\ pt\ (2):\ n_{H_2SO_4}=n_{Ca(OH)_2}=0,25\ mol.\\ \Rightarrow m_{\text{dd H$_2$SO$_4$}}=\dfrac{0,25\times 98}{20\%}=122,5\ g.\\ \Rightarrow V_{\text{dd H$_2$SO$_4$}}=\dfrac{122,5}{1,14}=107,456\ ml.\end{array}\)
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