Đáp án đúng: B
Giải chi tiết:\(\begin{gathered} \overline M S{O_4} + BaC{l_2} \to \overline M C{l_2} + Ba\,S{O_4} \hfill \\ 0,2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,2 \hfill \\ \overline M + 96 = \frac{{29,4}}{{0,2}} = 147 \hfill \\ \overline M = 51 \hfill \\ \end{gathered} \)
\(\begin{gathered} \left\{ \begin{gathered} 2{\text{A}} > 51 \hfill \\ B < 51 \hfill \\ \end{gathered} \right. \to \left\{ \begin{gathered} 2{\text{A > 51}} \hfill \\ A - 15 < 51 \hfill \\ \end{gathered} \right. \hfill \\ 25,5 < A < 66 \hfill \\ \end{gathered} \)
=> A=39(K)
=> B= 24 (Mg)
Đáp án B