Cho \(\dfrac{\text{a}}{b}=\dfrac{c}{d}.CM\)

\(\dfrac{3\text{a}+5b}{3\text{a}-5b}=\dfrac{3c+5d}{3c-5d}\)

\(\left(\dfrac{\text{a}+b}{c+d}\right)^2=\dfrac{\text{a}^2+b^2}{c^2+d^2}\)

Các câu hỏi liên quan