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Huyentrang98
2 năm trước
Cho phương trình x^2 - 2(m-5)x- 4m + 1 = 0 (m là tham số) a) Chứng minh phương trình luôn có hai nghiệm phân biệt với mọi m. b) Tìm m để phương trình có hai nghiệm x1, x2 thỏa 2(x2)^2 + 2(x2)^2+ (x1)^2.X2 + (x1)(x2)^2 = 10 Giúp em với khó quá ạ, chỉ rõ giúp em.
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