\(\left(2x-3\right)\left(6-2x\right)=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)
Vậy \(\left\{{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)