Đáp án + Giải thích các bước giải:
`a)`
`(6x+8)/(16x^{2}-1)-(2)/(4x+1)=(3)/(4x-1)` `(ĐK:x\ne+-(1)/(4))`
`<=>(6x+8-2(4x-1))/((4x-1)(4x+1))=(3(4x+1))/((4x-1)(4x+1))`
`=>6x+8-2(4x-1)=3(4x+1)`
`<=>6x+8-8x+2=12x+3`
`<=>-2x+10=12x+3`
`<=>12x+2x=10-3`
`<=>14x=7`
`<=>x=1/2\ (tm)`
`b)`
`(3)/(2x-16)+(3x-20)/(x-8)+(1)/(8)=(13x-102)/(3x-24)` `(ĐKXĐ:x\ne8)`
`<=>(3)/(2(x-8))+(3x-20)/(x-8)+(1)/(8)=(13x-102)/(3(x-8))`
`<=>(36+24(3x-20)+3(x-8))/(24(x-8))=(8(13x-102))/(24(x-8))`
`=>36+24(3x-20)+3(x-8)=8(13x-102)`
`<=>36+72x-480+3x-24=104x-816`
`<=>75x-468=104x-816`
`<=>104x-75x=816-468`
`<=>29x=348`
`<=>x=12\ (tm)`