Đáp án:
`s. \frac{8^8 xx 49^6}{14^{14}xx2^{10}}=\frac{2^{24}xx7^{12}}{7^{14}xx2^{14}xx2^{10}}=\frac{2^{14}xx1}{7^2 xx2^{14}}=1/(7^2)=1/49`
`t. \frac{(-3)^{28}xx25^{10}}{15^{19}xx27^3}=\frac{3^{28}xx5^{20}}{5^{19}xx3^{19}xx3^9}=\frac{3^{19}xx5}{3^{19}}=5`