Giải hệ phương trình: \(\left\{ \begin{array}{l}{x^2} + {y^2} + xy = 1\\x + y - xy = 2{y^2} - {x^2}\end{array} \right.\).
A.\(\left( {x;y} \right) = \left\{ {\left( {1; - 1} \right);\left( { - 1; - 1} \right);\left( {1;0} \right);\left( {\frac{3}{7};\frac{5}{7}} \right)} \right\}.\)
B.\(\left( {x;y} \right) = \left\{ {\left( {1; - 1} \right);\left( { - 1;1} \right);\left( { - 1;0} \right);\left( {\frac{3}{7};\frac{5}{7}} \right)} \right\}.\)
C.\(\left( {x;y} \right) = \left\{ {\left( {1;1} \right);\left( { - 1; - 1} \right);\left( { - 1;0} \right);\left( {\frac{3}{7};\frac{5}{7}} \right)} \right\}.\)
D.\(\left( {x;y} \right) = \left\{ {\left( {1; 1} \right);\left( { - 1;1} \right);\left( {1;0} \right);\left( {\frac{3}{7};\frac{5}{7}} \right)} \right\}.\)
A.\(\left( {x;y} \right) = \left\{ {\left( {1; - 1} \right);\left( { - 1; - 1} \right);\left( {1;0} \right);\left( {\frac{3}{7};\frac{5}{7}} \right)} \right\}.\)
B.\(\left( {x;y} \right) = \left\{ {\left( {1; - 1} \right);\left( { - 1;1} \right);\left( { - 1;0} \right);\left( {\frac{3}{7};\frac{5}{7}} \right)} \right\}.\)
C.\(\left( {x;y} \right) = \left\{ {\left( {1;1} \right);\left( { - 1; - 1} \right);\left( { - 1;0} \right);\left( {\frac{3}{7};\frac{5}{7}} \right)} \right\}.\)
D.\(\left( {x;y} \right) = \left\{ {\left( {1; 1} \right);\left( { - 1;1} \right);\left( {1;0} \right);\left( {\frac{3}{7};\frac{5}{7}} \right)} \right\}.\)
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Hóa Học lớp 12
