Câu a.
\(a{x^2}{y^3} - 2{x^2}{y^3} + {b^3}{x^2}{y^3} = (a - 2 + {b^2}){x^2}{y^3}\)
Câu b:
\(3u{v^2} - \left( {\frac{1}{5}u{v^2} + 367\frac{1}{4}u{v^2} - u{v^2}} \right) + \left( { - \frac{{19}}{5}u{v^2}} \right) + 367.\frac{1}{4}u{v^2}\)
\( = 3u{v^2} - \frac{1}{5}u{v^2} - 367.\frac{1}{4}u{v^2} + u{v^2} - \frac{{19}}{5}u{v^2} + 367.\frac{1}{4}u{v^2}\)
\( = (3u{v^2} + u{v^2}) + \left( { - \frac{1}{5}u{v^2} - \frac{{19}}{5}u{v^2}} \right) + \left( {367.\frac{1}{4}u{v^2} - 367.\frac{1}{4}u{v^2}} \right)\)
\( = 4u{v^2} - 4u{v^2} = 0\)
