Đáp án:
Giải thích các bước giải:
$1)
$a)3x-2=2x-3$
$⇔3x-2x=-3+2⇔x=-1$
$b)3-4y+24+6y=y+27+3y$
$2y+27=4y+27$
$⇔y=0$
$c)7-2x=22-3x$
$⇔-2x+3x+7-22=0$
$⇔x-15=0⇔x=15$
$2)$
$a)5-(x-6)=4.(3-2x)$
$⇔5-x+6=12-8x$
$⇔-x+11-12+8x=0$
$⇔7x+1=0⇔x=-\dfrac{1}{7}$
$b)2x.(x+2)^2-8x^2=2.(x-2).(x^2+2x+4)$
$⇔2x.(x^2+4x+4)-8x^2=2.(x^3-8)$
$⇔2x^3+8x^2+8x-8x^2=2x^3-16$
$⇔8x=-16$
$⇔x=-2$
$c)7-(2x+4)=-(x+4)$
$⇔7-2x-4=-x-4$
$⇔-x+2x-4+4-7=0$
$⇔x-7=0⇔x=7$
