Đáp án:
`x\in{1/3;-1/2}`
Trình bày lời giải:
`d)`
`(2x-2/3)(x+0,5)=0`
`=>`\(\left[ \begin{array}{l}2x-\dfrac{2}{3}=0\\x+0,5=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}2x=0+\dfrac{2}{3}\\x+\dfrac{1}{2}=0\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}2x=\dfrac{2}{3}\\x=0-\dfrac{1}{2}\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=\dfrac{2}{3}:2\\x=-\dfrac{1}{2}\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=\dfrac{2}{3}.\dfrac{1}{2}\\x=-\dfrac{1}{2}\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=-\dfrac{1}{2}\end{array} \right.\)
Vậy `x\in{1/3;-1/2}`
