$g, -5 + | 3x - 1 | + 6 = | -4 |$
$-5 + | 3x - 1 | + 6 = 4$
$( 6 - 5 ) + | 3x - 1 | = 4$
$1 + | 3x - 1 | = 4$
$| 3x - 1 | = 4 - 1$
$| 3x - 1 | = 3$
`=>` \(\left[ \begin{array}{l}3x-1=3\\3x-1=-3\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}3x=4\\3x=-2\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=\frac{4}{3} \\x=\frac{-2}{3}\end{array} \right.\)
$Vậy$ $x$ $∈$ { `4/3` ; `-2/3` }
