Đáp án:
\( \overline {{M_{hh}}} = 21,5\)
Giải thích các bước giải:
Ta có:
\({n_{C{O_2}}} = \frac{8}{{44}} = 0,2{\text{ mol}}\)
\({n_{{H_2}}} = \frac{{8,96}}{{22,4}} = 0,4{\text{ mol}}\)
\({n_N} = \frac{{{{6.10}^{23}}}}{{{{6.10}^{23}}}} = 1{\text{ mol}}\)
\( \to {n_{{N_2}}} = \frac{1}{2}{n_N} = 0,5{\text{ mol}}\)
\( \to {m_{hh}} = {m_{C{O_2}}} + {m_{{H_2}}} + {m_{{N_2}}} = 0,2.44 + 0,4.2 + 0,5.28 = 23,6{\text{ gam}}\)
\({n_{hh}} = {n_{C{O_2}}} + {n_{{H_2}}} + {n_{{N_2}}} = 0,2 + 0,4 + 0,5 = 1,1{\text{ mol}}\)
\( \to \overline {{M_{hh}}} = \frac{{23,6}}{{1,1}} = 21,5\)
