Đáp án:
Giải thích các bước giải:
$a/$
$CH_3COONa + NaOH \xrightarrow{t^o,CaO} Na_2CO_3 + CH_4$
$2CH_4 \xrightarrow{t^o,lln} C_2H_2 + 3H_2$
$C_2H_2 \xrightarrow{t^o,xt,p} CH≡C-CH=CH_2$
$C≡C-CH=CH_2 + 3H_2 \xrightarrow{t^o,Ni} CH_3-CH_2-CH_2-CH_3$
$C_4H_{10} \xrightarrow{t^o,Ni} C_3H_6 + CH_4$
$CH_2=CH-CH_3 + H_2O \xrightarrow{t^o.H^+} CH_3-CH(OH)-CH_3$
$b/$
$CH≡CH + HCl \xrightarrow{t^o,HgCl_2} CH_2=CH-Cl$
$CH_2=CH-Cl + NaOH → NaCl + CH_3-CHO$
$CH_3-CHO + \dfrac{1}{2}O_2 \xrightarrow{t^o} CH_3COOH$
$CH_3COOH + C_2H_5OH ⇄ CH_3COOC_2H_5 + H_2O$