$a,PTPƯ:Zn+2HCl\xrightarrow{} ZnCl_2+H_2↑$
$b,n_{Zn}=\dfrac{26}{65}=0,4mol.$
$Theo$ $pt:$ $n_{H_2}=n_{Zn}=0,4mol.$
$⇒V_{H_2}=0,4.22,4=8,96l.$
$c,Theo$ $pt:$ $n_{HCl}=2n_{Zn}=0,8mol.$
$⇒CM_{HCl}=\dfrac{0,8}{0,2}=4M.$
$d,PTPƯ:CuO+H_2\xrightarrow{t^o} Cu+H_2O$
$n_{CuO}=\dfrac{12}{80}=0,15mol.$
$\text{Lập tỉ lệ:}$ $\dfrac{0,15}{1}<\dfrac{0,4}{1}$
$⇒H_2$ $dư.$
$⇒n_{H_2}(dư)=0,4-\dfrac{0,15.1}{1}=0,25mol.$
$⇒m_{H_2}(dư)=0,25.2=0,5g.$
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