Đáp án:
Giải thích các bước giải:
$\lim _{x\to \:1}\left(\dfrac{x^4-1}{x^3-2x^2+1\:}\right)$
$\lim _{x\to \:1}\left(\dfrac{\left(x^2+1\right)\left(x-1\right)\left(x+1\right)}{\left(x-1\right)\left(x^2-x-1\right)\:}\right)$
$=\lim _{x\to \:1}\left(\dfrac{\left(x^2+1\right)\left(x+1\right)}{x^2-x-1}\right)$
$=\dfrac{\left(1^2+1\right)\left(1+1\right)}{1^2-1-1}$
$=-4$