Lập phương trình đường tiếp tuyến của đường tròn \(\left( C \right):\,\,\,{x^2} + {y^2} + 6x + 6y + 16 = 0\) biết tiếp tuyến vuông góc với đường thẳng \(d:\,\,\,x + y - 5 = 0.\)
A.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,x - y + 5 = 0\\{\Delta _2}:\,\,x - y - 5 = 0\end{array} \right.\)
B.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,x - y + 3 = 0\\{\Delta _2}:\,\,x - y - 3 = 0\end{array} \right.\)
C.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,x - y + 4 = 0\\{\Delta _2}:\,\,x - y - 4 = 0\end{array} \right.\)
D.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,x - y + 2 = 0\\{\Delta _2}:\,\,x - y - 2 = 0\end{array} \right.\)
A.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,x - y + 5 = 0\\{\Delta _2}:\,\,x - y - 5 = 0\end{array} \right.\)
B.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,x - y + 3 = 0\\{\Delta _2}:\,\,x - y - 3 = 0\end{array} \right.\)
C.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,x - y + 4 = 0\\{\Delta _2}:\,\,x - y - 4 = 0\end{array} \right.\)
D.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,x - y + 2 = 0\\{\Delta _2}:\,\,x - y - 2 = 0\end{array} \right.\)
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Hóa Học lớp 12
