c, I 3x - 2 I + 5= 9 - x
I 3x - 2 I = 9 - x - 5
I 3x - 2 I = 4 - x
=> \(\left[ \begin{array}{l}3x - 2 = 4 - x\\- (3x - 2) = 4 - x\end{array} \right.\)
=> \(\left[ \begin{array}{l}4x = 6\\-2x = 2\end{array} \right.\) => \(\left[ \begin{array}{l}x=\frac{3}{2} \\x=-1\end{array} \right.\)
d, (x + 7) - (x -9) = 0
=> \(\left[ \begin{array}{l}x+7=0\\x-9=0\end{array} \right.\) <=> \(\left[ \begin{array}{l}x = -7\\x=9\end{array} \right.\)
e, (x - 2) (5-x)= 0
\(\left[ \begin{array}{l}x-2=0\\5-x=0\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=2\\x=5\end{array} \right.\)
f, | 2x−5 |−7=22
<=> | 2x−5 |= 29
=> 2x− 5= ± 29
<=> \(\left[ \begin{array}{l}2x-5=29\\2x=5= -29\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=17\\x=-12\end{array} \right.\)
