Đáp án:
`1)x=-1/2`
`2)x=-12/5`
Giải thích các bước giải:
`1)(x+1)³-(x-1)³-6(x-1)²=-10`
`⇔x³+3.x².1+3.x.1²+1³-(x³-3.x².1+3.x.1²-1³)-6(x²-2.x.1+1²)=-10`
`⇔x³+3x²+3x+1-(x³-3x²+3x-1)-6(x²-2x+1)=-10`
`⇔x³+3x²+3x+1-x³+3x²-3x+1-6x²+12x-6=-10`
`⇔(x³-x³)+(3x²+3x²-6x²)+(3x-3x+12x)+(1+1-6)=-10`
`⇔12x-4=-10`
`⇔12x=-10+4`
`⇔12x=-6`
`⇔x=-6/12`
`⇔x=-1/2`
Vậy `x=-1/2`
`2)(x-2)³-x(x-1)(x+1)+6x(x-3)=4`
`⇔x³-3.x².2+3.x.2²-2³-x(x²-1)+6x²-18x=4`
`⇔x³-6x²+12x-8-x³+x+6x²-18x=4`
`⇔(x³-x³)+(-6x²+6x²)+(12x+x-18x)-8=4`
`⇔-5x-8=4`
`⇔-5x=4+8`
`⇔-5x=12`
`⇔x=-12/5`
Vậy `x=-12/5`
