Đáp án đúng: A Chọn đáp án A Ta có $A_{x}^{2}=100\Leftrightarrow \left\{ \begin{array}{l}x\ge 2\\\frac{x!}{\left( x-2 \right)!}=110\end{array} \right.\Leftrightarrow \left\{ \begin{array}{l}x\ge 2\\x\left( x-1 \right)=110\end{array} \right.$$\Leftrightarrow \left\{ \begin{array}{l}x\ge 2\\{{x}^{2}}-x-110=0\end{array} \right.\Leftrightarrow x=11$.