Rút gọn A=(1-a căn a/ 1- căn a + căn a)*(1+a căn a/ 1+ căn a - căn a)

Rut gon:

\(A=\left(\dfrac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a}\right)\left(\dfrac{1+a\sqrt{a}}{1+\sqrt{a}}-\sqrt{a}\right)\)

Rút gọn A=(4/x-cănx + cănx/cănx -1):1/cănx -1

Cho bieu thuc A=\(\left(\dfrac{4}{x-\sqrt{x}}+\dfrac{\sqrt{x}}{\sqrt{x}-1}\right)\div\dfrac{1}{\sqrt{x}-1}\)

a/ Tim dieu kien cua x de bieu thuc A co gia tri xac dinh

b/ Rut gon A

c/ Tinh gia tri cua A khi x = \(4-2\sqrt{3}\)

d/ Tim gia tri nho nhat cua A

Rút gọn căn(3-căn2)-căn(3+căn2)

Rut gon :\(\sqrt{3-\sqrt{2}}-\sqrt{3+\sqrt{2}}\)

Rút gọn M=n^3+2n^2-1/n^3+2n^2+2n+1

Rut gon : \(M=\dfrac{n^3+2n^2-1}{n^3+2n^2+2n+1}\)

Rút gọn A=căn((1+a^2)(1+b^2)(1+c^2))

cho a, b, c thoa man ab+bc+ca =1

rut gon ve dang ko chua can cua A= \(\sqrt{\left(1+a^2\right)\left(1+b^2\right)\left(1+c^2\right)}\)

please

Rút gọn A=căn(4-căn7)-căn(4+căn7)+căn7

giai giups nhanh nha,RUT GON

A=\(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}+\sqrt{7}\)

B=\(\sqrt{6.5+\sqrt{12}}+\sqrt{6.5-\sqrt{12}}+2\sqrt{6}\)

C=\(\sqrt{46+\sqrt{6\sqrt{5}}}-\sqrt{29-12\sqrt{5}}\)

D=\(\sqrt{13-\sqrt{160}}-\sqrt{53+4\sqrt{90}}\)

Rút gọn A=căn(9a^2-12a+4)-9a+1

cho minh hoi(rut gon)

A=\(\sqrt{9a^2-12a+4}-9a+1\)

Rút gọn B=cănx/cănx +4 + 4/cănx - 4): x+16/cănx +2

Cho cac bieu thuc :

\(A=\dfrac{\sqrt{x}+4}{\sqrt{x}+2},B=\left(\dfrac{\sqrt{x}}{\sqrt{x}+4}+\dfrac{4}{\sqrt{x}-4}\right):\dfrac{x+16}{\sqrt{x}+2}\)

a) Rut gon B ?

b) Tim cac gia tri nguyen cua x de cac gia tri cua bieu thuc B(A-1) la so nguyen.

Rút gọn biểu thức 3căn8- 4 căn18 +5 căn32 - căn 50

rút gọn biểu thức

a) \(3\sqrt{8}-4\sqrt{18}+5\sqrt{32}-\sqrt{50}\)

b) (\(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\)) : 10

c) \(2\sqrt{28}+2\sqrt{63}-3\sqrt{175}+\sqrt{112}\)

d) (\(\sqrt{14}-3\sqrt{2}\))\(^2\) +\(6\sqrt{28}\)

e) \(\sqrt{\left(1-\sqrt{2018}\right)^2}\). \(\sqrt{2019+2\sqrt{2018}}\)

f) \(\left(\sqrt{6}-\sqrt{5}\right)^2-\sqrt{120}\)

g)\(12\left(2\sqrt{3}-3\sqrt{2}\right)^2+2\sqrt{6}+3\sqrt{4}\)

Tính T=x căn(1+y^2)+ y căn(1+x^2)

Cho \(x\times y+\sqrt{\left(1+x^2\right)\left(1+y^2\right)}=2018\) . Tính \(T=x\sqrt{1+y^2}+y\sqrt{1+x^2}\) .