`a) A=9x^2+42x+49`
`A=(3x)^2+2.3x.7+7^2`
`A=(3x+7)^2`
Thay `x=-7/3` vào A ta có:
`A=(3. -7/3+7)^2=(-7+7)^2=0`
Vậy `A=0` khi `x=-7/3`
`b) B=25x^2-2xy+1/25y^2`
`B=(5x)^2-2.5x. 1/5y+(1/5y)^2`
`B=(5x-1/5y)^2`
Thay `x=-1/5;y=-5` vào B ta có:
`B=(5.(-1/5)-1/5.(-5))^2=(-1+1)^2=0`
Vậy `B=0` khi `x=-1/5;y=-5`