Tích phân $I=\int\limits_{0}^{1}{(x-2){{e}^{2x}}dx}$ bằng A. $\frac{5}{4}.$ B. $\frac{1}{4}(5+3{{e}^{2}}).$ C. $\frac{3}{4}(5-3{{e}^{2}}).$ D. $\frac{1}{4}(5-3{{e}^{2}}).$
Đáp án đúng: D Đặt $\left\{ \begin{array}{l}u=x-2\\dv={{e}^{2x}}dx\end{array} \right.=>\left\{ \begin{array}{l}du=dx\\v=\frac{{{e}^{2x}}}{2}\end{array} \right..$