a, |x-2|=2
⇒ \(\left[ \begin{array}{l}x-2=2\\x-2=-2\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=4\\x=0\end{array} \right.\)
Vậy x ∈ {4; 0}
b, |x+1|=2
⇒ \(\left[ \begin{array}{l}x+1=2\\x+1=-2\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=1\\x=-3\end{array} \right.\)
Vậy x ∈ {1; -3}
c, |x|=0
⇒ x = 0
Vậy x = 0