⇔ \(\dfrac{1}{1+\sqrt{x}}=1-\dfrac{1}{1+\sqrt{y}}+1-\dfrac{1}{1+\sqrt{z}}=\dfrac{\sqrt{y}}{1+\sqrt{y}}+\dfrac{\sqrt{z}}{1+\sqrt{z}}\text{≥}2\sqrt{\dfrac{\sqrt{yz}}{\left(1+\sqrt{y}\right)\left(1+\sqrt{z}\right)}}\) Làm tương tự : \(\dfrac{1}{1+\sqrt{y}}\text{≥}2\sqrt{\dfrac{\sqrt{xz}}{\left(1+\sqrt{x}\right)\left(1+\sqrt{z}\right)}}\)