Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}
DK:y \ne 0\\
\left\{ \begin{array}{l}
\frac{{x - y}}{{18}} = \frac{{y + 2}}{{27}}\\
\frac{{2x + y - 4}}{{9y}} = \frac{{y + 2}}{{27}}
\end{array} \right.\\
\to \left\{ \begin{array}{l}
2x - 2y = 3y + 6\\
2x + y - 4 = 3{y^2} + 6y
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x = \frac{{5y + 6}}{2}\\
5y + 6 + y - 4 = 3{y^2} + 6y
\end{array} \right.\\
\to \left[ \begin{array}{l}
y = \frac{{\sqrt 6 }}{3}\\
y = - \frac{{\sqrt 6 }}{3}
\end{array} \right.\left( {TM} \right) \to \left[ \begin{array}{l}
x = \frac{{18 + 5\sqrt 6 }}{6}\\
x = \frac{{18 - 5\sqrt 6 }}{6}
\end{array} \right.
\end{array}\)
