Ta có: 3x=2y \(\Rightarrow\dfrac{x}{2}=\dfrac{y}{3}\) ; 7y=5z\(\Rightarrow\dfrac{y}{5}=\dfrac{z}{7}\) \(\Rightarrow\left\{{}\begin{matrix}\dfrac{x}{2}=\dfrac{y}{3}\\\dfrac{y}{5}=\dfrac{z}{7}\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}\dfrac{x}{10}=\dfrac{y}{15}\\\dfrac{y}{15}=\dfrac{z}{21}\end{matrix}\right.\Rightarrow\dfrac{x}{10}=\dfrac{y}{15}=\dfrac{z}{21}\) Áp dụng tính chất dãy tỉ số bằng nhau: \(\dfrac{x}{10}=\dfrac{y}{15}=\dfrac{z}{21}=\dfrac{x-y+z}{10-15+21}=\dfrac{32}{16}=2\) \(\Rightarrow\left\{{}\begin{matrix}x=2.10=20\\y=2.15=30\\z=2.21=42\end{matrix}\right.\) Vậy x=20;y=30;z=42