Đáp án:
`=2^32+2^22+2^26-2^6-2^10`
Giải thích các bước giải:
`(2+1)(2^2+1)(2^4+1)(2^6+1)(2^8+1)(2^10+1)+1`
`=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^6+1)(2^10+1)+1`
`=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^6+1)(2^10+1)+1`
`=(2^4-1)(2^4+1)(2^8+1)(2^6+1)(2^10+1)+1`
`=(2^8-1)(2^8+1)(2^6+1)(2^10+1)+1`
`=(2^16-1)(2^6+1)(2^10+1)+1`
`=(2^16-1)(2^16+2^6+2^10+1)+1`
`=2^32+2^22+2^26+2^16-2^16-2^6-2^10-1+1`
`=2^32+2^22+2^26-2^6-2^10`