Đáp án:
\(\begin{array}{l}
\% {N_2} = 45,5\% \\
\% {O_2} = 54,5\%
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
hh\,A:{N_2}(a\,mol),{O_2}(b\,mol)\\
{M_A} = 15,09{M_{{H_2}}} = 30,18dvC\\
\Rightarrow \dfrac{{{m_{{N_2}}} + {m_{{O_2}}}}}{{{n_{{N_2}}} + {n_{{O_2}}}}} = 30,18 \Rightarrow \dfrac{{28a + 32b}}{{a + b}} = 30,18\\
\Rightarrow 28a + 32b = 30,18a + 30,18b\\
\Rightarrow 2,18a = 1,82b \Rightarrow \dfrac{a}{b} = \dfrac{{91}}{{109}}\\
\% {N_2} = \dfrac{{91}}{{91 + 109}} \times 100\% = 45,5\% \\
\% {O_2} = \dfrac{{109}}{{91 + 109}} \times 100\% = 54,5\%
\end{array}\)
