Với sự có mặt của oxi trong không khí, đồng bị tan trong dung dịch H2SO4 theo phản ứng sau:
A. $\displaystyle \text{Cu + }{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ }\!\!~\!\!\text{ }\to ~~\text{CuS}{{\text{O}}_{\text{4}}}\text{ }\!\!~\!\!\text{ + }{{\text{H}}_{\text{2}}}\text{.}$
B. $\displaystyle \text{2Cu + 2}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ }\!\!~\!\!\text{ + }{{\text{O}}_{\text{2}}}\text{ }\!\!~\!\!\text{ }\to ~~\text{2CuS}{{\text{O}}_{\text{4}}}\text{ }\!\!~\!\!\text{ + 2}{{\text{H}}_{\text{2}}}\text{O}$
C. $\displaystyle \text{Cu + 2}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ }\!\!~\!\!\text{ }\to \text{ }\!\!~\!\!\text{ CuS}{{\text{O}}_{\text{4}}}\text{ }\!\!~\!\!\text{ + S}{{\text{O}}_{\text{2}}}\text{ }\!\!~\!\!\text{ + 2}{{\text{H}}_{\text{2}}}\text{O}\text{. }\!\!~\!\!\text{ }~$
D. $\displaystyle \text{3Cu + 4}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{ }\!\!~\!\!\text{ + }{{\text{O}}_{\text{2}}}\text{ }\!\!~\!\!\text{ }\to \text{ 3CuS}{{\text{O}}_{\text{4}}}\text{ }\!\!~\!\!\text{ + S}{{\text{O}}_{\text{2}}}\text{ }\!\!~\!\!\text{ + 4}{{\text{H}}_{\text{2}}}\text{O}$
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