`P=(x-3\sqrt{x}+16)/(x)`
`P=1-3/\sqrt{x}+16/x`
`P=(4/(\sqrt{x}))^2-2. 4/(\sqrt{x}) . 3/8 +9/64+ 55/64`
`P=(4/(\sqrt{x})-3/8)^2+55/64>=55/64`
Dấu = xảy ra khi `4/(\sqrt{x})-3/8=0`
`<=>4/(\sqrt{x})=3/8`
`<=> \sqrt{x}=4.8:3`
`<=> \sqrt{x}=32/3`
`<=> x=(32/3)^2`
`<=> x=1024/9`
Vậy `P_(min)=55/64 <=> x=1024/9`