`text{@dg}`
`text{a) Với x=15, ta có:}`
`5x.(4x^2-2x+1)-2x.(10x^2-5x-2)`
`=5.15.(4.15^2-2.15+1)-2.15.(10.15^2-5.15-2)`
`=75.(4.225-30+1)-30.(10.225-75-2)`
`=75.(900-30+1)-30.(2250-75-2)`
`=75.871-30.2173)`
`=65325-65190`
`=135`
`text{b) Với x=-1/5, y=-1/2, ta có:}`
$5x.(x-4y) -4y.(y-5x)$
`=5.(-1/5).(-1/5-4.-1/2)-4.-1/2.(-1/2-5.-1/5)`
`=-1.(-1/5+2)+2.(-1/2+1)`
`=-1.9/5+2.1/2`
`=-9/5+1`
`=-4/5`
`text{c) Với x=1/2, y=2, ta có:}`
`6xy. ( xy-y²) -8x².(x-y²) +5y².( x²-xy)`
$=6.1/2 .2.(1/2.2-2^2)-8.(1/2)^2.(1/2-2^2)+5.2^2.((1/2)^2-1/2.2)$
$=6.(1-4)-2.(1/2-4)+20.(1/4-1)$
$=6.(-3)-2.(-7/2)+20.(-3/4)$
`=-18+7-15`
`=-26`