1)
B = -2x2 + 8x - 15
= -2.(x2 - 4x + 4) + 8 - 15
= -2.(x - 2)2 - 7 \(\le\) - 7 với \(\forall\) x
Dấu " =" xảy ra khi (x - 2)2 = 0 => x = 2
Vậy Bmax = - 7 <=> x = 2
2)
C = - 3x2 + 2x - 1
= - 3(x2 - \(2.\dfrac{1}{3}\).x + \(\dfrac{1}{9}\) ) + \(\dfrac{1}{3}\) - 1
= - 3.(x - \(\dfrac{1}{3}\) )2 - \(\dfrac{2}{3}\) \(\le\) - \(\dfrac{2}{3}\) với \(\forall\) x
Dấu " =" xảy ra khi (x - \(\dfrac{1}{3}\) )2 = 0 => x = \(\dfrac{1}{3}\)
Vậy Cmax = - \(\dfrac{2}{3}\) <=> x = \(\dfrac{1}{3}\)
3)
D = - 3x2 + 4x - 1
= - 3(x2 - \(2.\dfrac{2}{3}\).x + \(\dfrac{4}{9}\) ) - \(\dfrac{4}{3}\) - 1
= - 3.(x - \(\dfrac{2}{3}\) )2 - \(\dfrac{7}{3}\) \(\le\) - \(\dfrac{7}{3}\) với \(\forall\) x
Dấu " =" xảy ra khi (x - \(\dfrac{2}{3}\) )2 = 0 => x = \(\dfrac{2}{3}\)
Vậy Dmax = - \(\dfrac{7}{3}\) <=> x = \(\dfrac{2}{3}\)