Nghiệm của bất phương trình ${{\log }_{2}}\left( {\frac{{{{x}^{2}}-2x+4}}{{2x-3}}} \right)-2{{\log }_{2}}\left( {\frac{{{{x}^{2}}-8x+13}}{{{{x}^{2}}-12x+19}}} \right)\ge 2$ là?
A. $\left( {\frac{3}{2};10-\sqrt{{69}}} \right]\cup \left( {4-\sqrt{3};4+\sqrt{3}} \right)\cup \left[ {10+\sqrt{{69}};+\infty } \right).$
B. $\left( {\frac{3}{2};10-\sqrt{{69}}} \right]\cup \left[ {10+\sqrt{{69}};+\infty } \right).$
C. $\left( {4-\sqrt{3};4+\sqrt{3}} \right)\cup \left[ {10+\sqrt{{69}};+\infty } \right).$
D. $\left( {\frac{3}{2};10-\sqrt{{69}}} \right]\cup \left( {4-\sqrt{3};4+\sqrt{3}} \right).$
A. $\left( {\frac{3}{2};10-\sqrt{{69}}} \right]\cup \left( {4-\sqrt{3};4+\sqrt{3}} \right)\cup \left[ {10+\sqrt{{69}};+\infty } \right).$
B. $\left( {\frac{3}{2};10-\sqrt{{69}}} \right]\cup \left[ {10+\sqrt{{69}};+\infty } \right).$
C. $\left( {4-\sqrt{3};4+\sqrt{3}} \right)\cup \left[ {10+\sqrt{{69}};+\infty } \right).$
D. $\left( {\frac{3}{2};10-\sqrt{{69}}} \right]\cup \left( {4-\sqrt{3};4+\sqrt{3}} \right).$
Loga
Hóa Học lớp 12
