a,/x/=$\frac{1}{5}$+$\frac{3}{4}$
<=>/x/=$\frac{14}{20}$+$\frac{15}{20}$
<=>/x/=$\frac{19}{20}$
=>\(\left[ \begin{array}{l}x=\frac{19}{20}\\x=-\frac{19}{20}\end{array} \right.\)
vậy x=$\frac{19}{20}$ hoặc x=-$\frac{19}{20}$
b, /x-5/=-(-$\frac{5}{3}$)+$\frac{1}{4}$
<=>/x+5/=$\frac{20}{12}$+$\frac{3}{12}$
<=>/x=5/=$\frac{23}{12}$
=>\(\left[ \begin{array}{l}x-5=\frac{23}{12}\\x-5=-\frac{23}{12}\end{array} \right.\)
<=>\(\left[ \begin{array}{l}x=\frac{83}{12}\\x=\frac{37}{12}\end{array} \right.\)
Vậy x=$\frac{83}{12}$ hoặc x=$\frac{37}{12}$
#xin 5 sao+ ctlhn
