Nguyên hàm $\int{{\frac{{{{{(x-1)}}^{2}}}}{{{{{(2x+1)}}^{4}}}}dx}}$ bằng?
A. ${{\left( {\frac{{x-1}}{{2x+1}}} \right)}^{3}}+C.$
B. $\frac{1}{6}{{\left( {\frac{{x-1}}{{2x+1}}} \right)}^{3}}+C.$
C. $\frac{1}{9}{{\left( {\frac{{x-1}}{{2x+1}}} \right)}^{3}}+C.$
D. $\frac{1}{3}{{\left( {\frac{{x-1}}{{2x+1}}} \right)}^{3}}+C.$