$\textrm{Vì ΔABC cân tại A}$
$\widehat{B}=\widehat{C}$ $(1)$
$\widehat{A}+\widehat{B}+\widehat{C}=180^{0}$
$⇒\widehat{B}+\widehat{C}=180^{0}-\widehat{A}=180^{0}-50^{0}$
$⇒\widehat{B}+\widehat{C}=130^{0}$ $(2)$
$⇒\widehat{B}=\widehat{C}=\frac{130^{0}}{2}=65^{0}$