Đáp án : $x=(\dfrac{1}{196}+\dfrac{589}{197}-\dfrac{399}{198}):(\dfrac{1}{196}+\dfrac{1}{197}+\dfrac{1}{198})$
Giải thích các bước giải:
$\dfrac{x-1}{196}+\dfrac{x-589}{197}+\dfrac{x+399}{198}=0$
$\to (\dfrac{x}{196}+\dfrac{x}{197}+\dfrac{x}{198})-(\dfrac{1}{196}+\dfrac{589}{197}-\dfrac{399}{198})=0$
$\to x(\dfrac{1}{196}+\dfrac{1}{197}+\dfrac{1}{198})=(\dfrac{1}{196}+\dfrac{589}{197}-\dfrac{399}{198})$
$\to x=(\dfrac{1}{196}+\dfrac{589}{197}-\dfrac{399}{198}):(\dfrac{1}{196}+\dfrac{1}{197}+\dfrac{1}{198})$