Đáp án:
B11:
5) \(\left[ \begin{array}{l}
x = 1\\
x = - 2\\
x = - 3
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
B10\\
1)2x - 5 = - 11\\
\to 2x = - 6\\
\to x = - 3\\
2)2\left( {4 - 3x} \right) = 14\\
\to 4 - 3x = 7\\
\to 3x = - 3\\
\to x = - 1\\
3)3\left( { - x + 7} \right) = - 6\\
\to 7 - x = - 2\\
\to x = 9\\
4)3x - 2 = 24:\left( { - 3} \right)\\
\to 3x - 2 = 8\\
\to 3x = 10\\
\to x = \dfrac{{10}}{3}\\
5)5\left( { - 3 - 2x} \right) = - 15\\
\to - 3 - 2x = - 3\\
\to - 2x = 0\\
\to x = 0\\
B11:\\
1)\left[ \begin{array}{l}
x = 0\\
x + 7 = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 0\\
x = - 7
\end{array} \right.\\
2)\left[ \begin{array}{l}
x + 12 = 0\\
x - 3 = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = - 12\\
x = 3
\end{array} \right.\\
3)\left[ \begin{array}{l}
- x + 5 = 0\\
3 - x = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 5\\
x = 3
\end{array} \right.\\
4)\left[ \begin{array}{l}
x = 0\\
x + 2 = 0\\
7 - x = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 0\\
x = - 2\\
x = 7
\end{array} \right.\\
5)\left[ \begin{array}{l}
x - 1 = 0\\
x + 2 = 0\\
- x - 3 = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 1\\
x = - 2\\
x = - 3
\end{array} \right.
\end{array}\)
