(x + 3)(x + 4)(x + 5) = x
<=> (x2 + 3x + 4x + 12)(x + 5) - x = 0
<=> (x2 + 7x + 12)(x + 5) - x = 0
<=> x3 + 7x2 + 12x + 5x2 + 35x + 60 - x = 0
<=> x3 + 12x2 + 46x + 60 = 0
<=> x3 + 6x2 + 6x2 + 36x + 10x + 60 = 0
<=> (x + 6)(x2 + 6x + 10) = 0
<=> (x + 6)[(x + 3)2 + 1] = 0
=> x + 6 = 0 => x = -6