Đáp án đúng: C
Giải chi tiết:\(\begin{array}{l}G/s:\,{n_{{N_2}bd}} = 1\,mol;\,{n_{{H_2}bd}} = x\,mol.\\{n_{{N_2}pu}} = 1.\frac{{10}}{{100}} = 0,1\,mol.\\\,\,\,\,\,\,\,\,\,\,\,\,\,{N_2} + {\rm{ }}3{\rm{ }}{H_2}2N{H_3}\\Bd:\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,x\\Pu:\,\,\,\,\,0,1\,\,\,\,\,\,0,3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,2\\Sau:\,\,\,0,9\,\,\,\,\,x - 0,3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,2\\{n_{bd}} = 1 + x\,(mol);\,{n_s} = 0,8 + x\,(mol)\\\frac{{{n_d}}}{{{n_s}}} = \frac{{{p_d}}}{{{p_s}}} = > \frac{{1 + x}}{{0,8 + x}} = \frac{{100}}{{95}} = > x = 3\,mol.\\\% {V_{{N_2}}} = \frac{1}{{1 + 3}}.100\% = 25\% \\\% {V_{{H_2}}}\, = 75\% \end{array}\)